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Derivation of Kinetic energy


Posted Date:     Total Responses: 0    Posted By: C.N.Anantharaman   Member Level: Gold   Points/Cash: 4   


The kinetic energy of a body is the work done by it before coming to rest.
Suppose a body of mass "m" is at position "A".Let it enter into a medium "M" which opposes the motion of the body with a constant force "F".As a result, the body will be constantly retarded and comes to rest at position "B".By going through the distance "S" against the opposing force "F", the body has done some work.

work done = Force*Displacement

v2(spelt "v" square) = u2-2as

v2 = v2-2as

0 = v2 - 2as

u (or) v = Initial velocity

v = Final velocity

a = accleration( -a )

s = distance

0 = v2-2as

f = m * a

a = f/m

v2 = 2*f*s/m

transpose "m" to the other side

mv2 = 2*f*s

work done = fs=ke

2*ke = mv2

K.E. = mv/2

K.E. = 1/2 mv2

(Hence Proved).


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